I'm a beginner using verilog. I am trying to make a simple parallel to serial converter (8 bits parallel down to 1 bit serial). I have 2 textbooks but I think it is way too complicated for me to understand. Right now when I try to simulate my simple Parallel-to-Serial module the input of 8-bits parallel appear but only 1 of the 8 serial bit appear.

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Design of Serial IN - Parallel Out Shift Register using Behavior Modeling Style - Output Waveform: Serial IN - Parallel OUT Shift Register Verilog CODE- //----------------------------------------------------------------------------- // // Title: SIPO // Design: verilog upload 2 // Author: Naresh Singh Dobal // Company: nsdobal@gmail.com // Verilog Programs & Exercise by Naresh Singh Dobal. // //----------------------------------------------------------------------------- // // File: Serial IN Parallel OUT Shift Register using Behavior Modeling Style.v module SIPO ( din,clk,reset,dout ); output [3:0] dout; wire [3:0] dout; input din; wire din; input clk; wire clk; input reset; wire reset; reg [3:0]s; always @ (posedge (clk)) begin if (reset) s.

There is no pin for synchronization. The RS-232 serial protocol has a start and stop bit, logic 0 and 1 respectively. An idle channel will have a logic 1. So if the channel goes from idle to active, 0 will be the first thing you see. If you pick up the channel in the middle of transmission you'll end up having to find the pattern of 10 repeating every 10 bits (8-bit data).

I actually don't think anyone does that type of synchronization. From observation of devices that used RS-232 to receive data, I always remember seeing garbage if you hooked it up in the middle of a burst of data. I think most devices need a pause before achieving synchornization.